3.13.80 \(\int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx\)

Optimal. Leaf size=218 \[ -\frac {7 d^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}}+\frac {7 d^4 \sqrt {c+d x}}{128 b (a+b x) (b c-a d)^4}-\frac {7 d^3 \sqrt {c+d x}}{192 b (a+b x)^2 (b c-a d)^3}+\frac {7 d^2 \sqrt {c+d x}}{240 b (a+b x)^3 (b c-a d)^2}-\frac {d \sqrt {c+d x}}{40 b (a+b x)^4 (b c-a d)}-\frac {\sqrt {c+d x}}{5 b (a+b x)^5} \]

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Rubi [A]  time = 0.15, antiderivative size = 218, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {47, 51, 63, 208} \begin {gather*} -\frac {7 d^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}}+\frac {7 d^4 \sqrt {c+d x}}{128 b (a+b x) (b c-a d)^4}-\frac {7 d^3 \sqrt {c+d x}}{192 b (a+b x)^2 (b c-a d)^3}+\frac {7 d^2 \sqrt {c+d x}}{240 b (a+b x)^3 (b c-a d)^2}-\frac {d \sqrt {c+d x}}{40 b (a+b x)^4 (b c-a d)}-\frac {\sqrt {c+d x}}{5 b (a+b x)^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[c + d*x]/(a + b*x)^6,x]

[Out]

-Sqrt[c + d*x]/(5*b*(a + b*x)^5) - (d*Sqrt[c + d*x])/(40*b*(b*c - a*d)*(a + b*x)^4) + (7*d^2*Sqrt[c + d*x])/(2
40*b*(b*c - a*d)^2*(a + b*x)^3) - (7*d^3*Sqrt[c + d*x])/(192*b*(b*c - a*d)^3*(a + b*x)^2) + (7*d^4*Sqrt[c + d*
x])/(128*b*(b*c - a*d)^4*(a + b*x)) - (7*d^5*ArcTanh[(Sqrt[b]*Sqrt[c + d*x])/Sqrt[b*c - a*d]])/(128*b^(3/2)*(b
*c - a*d)^(9/2))

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin {align*} \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}+\frac {d \int \frac {1}{(a+b x)^5 \sqrt {c+d x}} \, dx}{10 b}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}-\frac {\left (7 d^2\right ) \int \frac {1}{(a+b x)^4 \sqrt {c+d x}} \, dx}{80 b (b c-a d)}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}+\frac {\left (7 d^3\right ) \int \frac {1}{(a+b x)^3 \sqrt {c+d x}} \, dx}{96 b (b c-a d)^2}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}-\frac {\left (7 d^4\right ) \int \frac {1}{(a+b x)^2 \sqrt {c+d x}} \, dx}{128 b (b c-a d)^3}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}+\frac {\left (7 d^5\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx}{256 b (b c-a d)^4}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}+\frac {\left (7 d^4\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{128 b (b c-a d)^4}\\ &=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}-\frac {7 d^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}}\\ \end {align*}

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Mathematica [C]  time = 0.02, size = 52, normalized size = 0.24 \begin {gather*} \frac {2 d^5 (c+d x)^{3/2} \, _2F_1\left (\frac {3}{2},6;\frac {5}{2};-\frac {b (c+d x)}{a d-b c}\right )}{3 (a d-b c)^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[c + d*x]/(a + b*x)^6,x]

[Out]

(2*d^5*(c + d*x)^(3/2)*Hypergeometric2F1[3/2, 6, 5/2, -((b*(c + d*x))/(-(b*c) + a*d))])/(3*(-(b*c) + a*d)^6)

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IntegrateAlgebraic [A]  time = 1.52, size = 317, normalized size = 1.45 \begin {gather*} \frac {d^5 \sqrt {c+d x} \left (105 a^4 d^4-790 a^3 b d^3 (c+d x)-420 a^3 b c d^3+630 a^2 b^2 c^2 d^2-896 a^2 b^2 d^2 (c+d x)^2+2370 a^2 b^2 c d^2 (c+d x)-420 a b^3 c^3 d-2370 a b^3 c^2 d (c+d x)-490 a b^3 d (c+d x)^3+1792 a b^3 c d (c+d x)^2+105 b^4 c^4+790 b^4 c^3 (c+d x)-896 b^4 c^2 (c+d x)^2-105 b^4 (c+d x)^4+490 b^4 c (c+d x)^3\right )}{1920 b (b c-a d)^4 (-a d-b (c+d x)+b c)^5}-\frac {7 d^5 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x} \sqrt {a d-b c}}{b c-a d}\right )}{128 b^{3/2} (b c-a d)^4 \sqrt {a d-b c}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[Sqrt[c + d*x]/(a + b*x)^6,x]

[Out]

(d^5*Sqrt[c + d*x]*(105*b^4*c^4 - 420*a*b^3*c^3*d + 630*a^2*b^2*c^2*d^2 - 420*a^3*b*c*d^3 + 105*a^4*d^4 + 790*
b^4*c^3*(c + d*x) - 2370*a*b^3*c^2*d*(c + d*x) + 2370*a^2*b^2*c*d^2*(c + d*x) - 790*a^3*b*d^3*(c + d*x) - 896*
b^4*c^2*(c + d*x)^2 + 1792*a*b^3*c*d*(c + d*x)^2 - 896*a^2*b^2*d^2*(c + d*x)^2 + 490*b^4*c*(c + d*x)^3 - 490*a
*b^3*d*(c + d*x)^3 - 105*b^4*(c + d*x)^4))/(1920*b*(b*c - a*d)^4*(b*c - a*d - b*(c + d*x))^5) - (7*d^5*ArcTan[
(Sqrt[b]*Sqrt[-(b*c) + a*d]*Sqrt[c + d*x])/(b*c - a*d)])/(128*b^(3/2)*(b*c - a*d)^4*Sqrt[-(b*c) + a*d])

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fricas [B]  time = 1.34, size = 1673, normalized size = 7.67

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^(1/2)/(b*x+a)^6,x, algorithm="fricas")

[Out]

[1/3840*(105*(b^5*d^5*x^5 + 5*a*b^4*d^5*x^4 + 10*a^2*b^3*d^5*x^3 + 10*a^3*b^2*d^5*x^2 + 5*a^4*b*d^5*x + a^5*d^
5)*sqrt(b^2*c - a*b*d)*log((b*d*x + 2*b*c - a*d - 2*sqrt(b^2*c - a*b*d)*sqrt(d*x + c))/(b*x + a)) - 2*(384*b^6
*c^5 - 1872*a*b^5*c^4*d + 3592*a^2*b^4*c^3*d^2 - 3314*a^3*b^3*c^2*d^3 + 1315*a^4*b^2*c*d^4 - 105*a^5*b*d^5 - 1
05*(b^6*c*d^4 - a*b^5*d^5)*x^4 + 70*(b^6*c^2*d^3 - 8*a*b^5*c*d^4 + 7*a^2*b^4*d^5)*x^3 - 14*(4*b^6*c^3*d^2 - 27
*a*b^5*c^2*d^3 + 87*a^2*b^4*c*d^4 - 64*a^3*b^3*d^5)*x^2 + 2*(24*b^6*c^4*d - 152*a*b^5*c^3*d^2 + 417*a^2*b^4*c^
2*d^3 - 684*a^3*b^3*c*d^4 + 395*a^4*b^2*d^5)*x)*sqrt(d*x + c))/(a^5*b^7*c^5 - 5*a^6*b^6*c^4*d + 10*a^7*b^5*c^3
*d^2 - 10*a^8*b^4*c^2*d^3 + 5*a^9*b^3*c*d^4 - a^10*b^2*d^5 + (b^12*c^5 - 5*a*b^11*c^4*d + 10*a^2*b^10*c^3*d^2
- 10*a^3*b^9*c^2*d^3 + 5*a^4*b^8*c*d^4 - a^5*b^7*d^5)*x^5 + 5*(a*b^11*c^5 - 5*a^2*b^10*c^4*d + 10*a^3*b^9*c^3*
d^2 - 10*a^4*b^8*c^2*d^3 + 5*a^5*b^7*c*d^4 - a^6*b^6*d^5)*x^4 + 10*(a^2*b^10*c^5 - 5*a^3*b^9*c^4*d + 10*a^4*b^
8*c^3*d^2 - 10*a^5*b^7*c^2*d^3 + 5*a^6*b^6*c*d^4 - a^7*b^5*d^5)*x^3 + 10*(a^3*b^9*c^5 - 5*a^4*b^8*c^4*d + 10*a
^5*b^7*c^3*d^2 - 10*a^6*b^6*c^2*d^3 + 5*a^7*b^5*c*d^4 - a^8*b^4*d^5)*x^2 + 5*(a^4*b^8*c^5 - 5*a^5*b^7*c^4*d +
10*a^6*b^6*c^3*d^2 - 10*a^7*b^5*c^2*d^3 + 5*a^8*b^4*c*d^4 - a^9*b^3*d^5)*x), 1/1920*(105*(b^5*d^5*x^5 + 5*a*b^
4*d^5*x^4 + 10*a^2*b^3*d^5*x^3 + 10*a^3*b^2*d^5*x^2 + 5*a^4*b*d^5*x + a^5*d^5)*sqrt(-b^2*c + a*b*d)*arctan(sqr
t(-b^2*c + a*b*d)*sqrt(d*x + c)/(b*d*x + b*c)) - (384*b^6*c^5 - 1872*a*b^5*c^4*d + 3592*a^2*b^4*c^3*d^2 - 3314
*a^3*b^3*c^2*d^3 + 1315*a^4*b^2*c*d^4 - 105*a^5*b*d^5 - 105*(b^6*c*d^4 - a*b^5*d^5)*x^4 + 70*(b^6*c^2*d^3 - 8*
a*b^5*c*d^4 + 7*a^2*b^4*d^5)*x^3 - 14*(4*b^6*c^3*d^2 - 27*a*b^5*c^2*d^3 + 87*a^2*b^4*c*d^4 - 64*a^3*b^3*d^5)*x
^2 + 2*(24*b^6*c^4*d - 152*a*b^5*c^3*d^2 + 417*a^2*b^4*c^2*d^3 - 684*a^3*b^3*c*d^4 + 395*a^4*b^2*d^5)*x)*sqrt(
d*x + c))/(a^5*b^7*c^5 - 5*a^6*b^6*c^4*d + 10*a^7*b^5*c^3*d^2 - 10*a^8*b^4*c^2*d^3 + 5*a^9*b^3*c*d^4 - a^10*b^
2*d^5 + (b^12*c^5 - 5*a*b^11*c^4*d + 10*a^2*b^10*c^3*d^2 - 10*a^3*b^9*c^2*d^3 + 5*a^4*b^8*c*d^4 - a^5*b^7*d^5)
*x^5 + 5*(a*b^11*c^5 - 5*a^2*b^10*c^4*d + 10*a^3*b^9*c^3*d^2 - 10*a^4*b^8*c^2*d^3 + 5*a^5*b^7*c*d^4 - a^6*b^6*
d^5)*x^4 + 10*(a^2*b^10*c^5 - 5*a^3*b^9*c^4*d + 10*a^4*b^8*c^3*d^2 - 10*a^5*b^7*c^2*d^3 + 5*a^6*b^6*c*d^4 - a^
7*b^5*d^5)*x^3 + 10*(a^3*b^9*c^5 - 5*a^4*b^8*c^4*d + 10*a^5*b^7*c^3*d^2 - 10*a^6*b^6*c^2*d^3 + 5*a^7*b^5*c*d^4
- a^8*b^4*d^5)*x^2 + 5*(a^4*b^8*c^5 - 5*a^5*b^7*c^4*d + 10*a^6*b^6*c^3*d^2 - 10*a^7*b^5*c^2*d^3 + 5*a^8*b^4*c
*d^4 - a^9*b^3*d^5)*x)]

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giac [B]  time = 1.47, size = 432, normalized size = 1.98 \begin {gather*} \frac {7 \, d^{5} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{128 \, {\left (b^{5} c^{4} - 4 \, a b^{4} c^{3} d + 6 \, a^{2} b^{3} c^{2} d^{2} - 4 \, a^{3} b^{2} c d^{3} + a^{4} b d^{4}\right )} \sqrt {-b^{2} c + a b d}} + \frac {105 \, {\left (d x + c\right )}^{\frac {9}{2}} b^{4} d^{5} - 490 \, {\left (d x + c\right )}^{\frac {7}{2}} b^{4} c d^{5} + 896 \, {\left (d x + c\right )}^{\frac {5}{2}} b^{4} c^{2} d^{5} - 790 \, {\left (d x + c\right )}^{\frac {3}{2}} b^{4} c^{3} d^{5} - 105 \, \sqrt {d x + c} b^{4} c^{4} d^{5} + 490 \, {\left (d x + c\right )}^{\frac {7}{2}} a b^{3} d^{6} - 1792 \, {\left (d x + c\right )}^{\frac {5}{2}} a b^{3} c d^{6} + 2370 \, {\left (d x + c\right )}^{\frac {3}{2}} a b^{3} c^{2} d^{6} + 420 \, \sqrt {d x + c} a b^{3} c^{3} d^{6} + 896 \, {\left (d x + c\right )}^{\frac {5}{2}} a^{2} b^{2} d^{7} - 2370 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{2} b^{2} c d^{7} - 630 \, \sqrt {d x + c} a^{2} b^{2} c^{2} d^{7} + 790 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{3} b d^{8} + 420 \, \sqrt {d x + c} a^{3} b c d^{8} - 105 \, \sqrt {d x + c} a^{4} d^{9}}{1920 \, {\left (b^{5} c^{4} - 4 \, a b^{4} c^{3} d + 6 \, a^{2} b^{3} c^{2} d^{2} - 4 \, a^{3} b^{2} c d^{3} + a^{4} b d^{4}\right )} {\left ({\left (d x + c\right )} b - b c + a d\right )}^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^(1/2)/(b*x+a)^6,x, algorithm="giac")

[Out]

7/128*d^5*arctan(sqrt(d*x + c)*b/sqrt(-b^2*c + a*b*d))/((b^5*c^4 - 4*a*b^4*c^3*d + 6*a^2*b^3*c^2*d^2 - 4*a^3*b
^2*c*d^3 + a^4*b*d^4)*sqrt(-b^2*c + a*b*d)) + 1/1920*(105*(d*x + c)^(9/2)*b^4*d^5 - 490*(d*x + c)^(7/2)*b^4*c*
d^5 + 896*(d*x + c)^(5/2)*b^4*c^2*d^5 - 790*(d*x + c)^(3/2)*b^4*c^3*d^5 - 105*sqrt(d*x + c)*b^4*c^4*d^5 + 490*
(d*x + c)^(7/2)*a*b^3*d^6 - 1792*(d*x + c)^(5/2)*a*b^3*c*d^6 + 2370*(d*x + c)^(3/2)*a*b^3*c^2*d^6 + 420*sqrt(d
*x + c)*a*b^3*c^3*d^6 + 896*(d*x + c)^(5/2)*a^2*b^2*d^7 - 2370*(d*x + c)^(3/2)*a^2*b^2*c*d^7 - 630*sqrt(d*x +
c)*a^2*b^2*c^2*d^7 + 790*(d*x + c)^(3/2)*a^3*b*d^8 + 420*sqrt(d*x + c)*a^3*b*c*d^8 - 105*sqrt(d*x + c)*a^4*d^9
)/((b^5*c^4 - 4*a*b^4*c^3*d + 6*a^2*b^3*c^2*d^2 - 4*a^3*b^2*c*d^3 + a^4*b*d^4)*((d*x + c)*b - b*c + a*d)^5)

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maple [A]  time = 0.02, size = 337, normalized size = 1.55 \begin {gather*} \frac {7 \left (d x +c \right )^{\frac {9}{2}} b^{3} d^{5}}{128 \left (b d x +a d \right )^{5} \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right )}+\frac {49 \left (d x +c \right )^{\frac {7}{2}} b^{2} d^{5}}{192 \left (b d x +a d \right )^{5} \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}+\frac {7 \left (d x +c \right )^{\frac {5}{2}} b \,d^{5}}{15 \left (b d x +a d \right )^{5} \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {7 d^{5} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{128 \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \sqrt {\left (a d -b c \right ) b}\, b}+\frac {79 \left (d x +c \right )^{\frac {3}{2}} d^{5}}{192 \left (b d x +a d \right )^{5} \left (a d -b c \right )}-\frac {7 \sqrt {d x +c}\, d^{5}}{128 \left (b d x +a d \right )^{5} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x+c)^(1/2)/(b*x+a)^6,x)

[Out]

7/128*d^5/(b*d*x+a*d)^5*b^3/(a^4*d^4-4*a^3*b*c*d^3+6*a^2*b^2*c^2*d^2-4*a*b^3*c^3*d+b^4*c^4)*(d*x+c)^(9/2)+49/1
92*d^5/(b*d*x+a*d)^5*b^2/(a^3*d^3-3*a^2*b*c*d^2+3*a*b^2*c^2*d-b^3*c^3)*(d*x+c)^(7/2)+7/15*d^5/(b*d*x+a*d)^5*b/
(a^2*d^2-2*a*b*c*d+b^2*c^2)*(d*x+c)^(5/2)+79/192*d^5/(b*d*x+a*d)^5/(a*d-b*c)*(d*x+c)^(3/2)-7/128*d^5/(b*d*x+a*
d)^5/b*(d*x+c)^(1/2)+7/128*d^5/b/(a^4*d^4-4*a^3*b*c*d^3+6*a^2*b^2*c^2*d^2-4*a*b^3*c^3*d+b^4*c^4)/((a*d-b*c)*b)
^(1/2)*arctan((d*x+c)^(1/2)/((a*d-b*c)*b)^(1/2)*b)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^(1/2)/(b*x+a)^6,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for
more details)Is a*d-b*c positive or negative?

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mupad [B]  time = 0.49, size = 401, normalized size = 1.84 \begin {gather*} \frac {\frac {79\,d^5\,{\left (c+d\,x\right )}^{3/2}}{192\,\left (a\,d-b\,c\right )}-\frac {7\,d^5\,\sqrt {c+d\,x}}{128\,b}+\frac {49\,b^2\,d^5\,{\left (c+d\,x\right )}^{7/2}}{192\,{\left (a\,d-b\,c\right )}^3}+\frac {7\,b^3\,d^5\,{\left (c+d\,x\right )}^{9/2}}{128\,{\left (a\,d-b\,c\right )}^4}+\frac {7\,b\,d^5\,{\left (c+d\,x\right )}^{5/2}}{15\,{\left (a\,d-b\,c\right )}^2}}{b^5\,{\left (c+d\,x\right )}^5-{\left (c+d\,x\right )}^2\,\left (-10\,a^3\,b^2\,d^3+30\,a^2\,b^3\,c\,d^2-30\,a\,b^4\,c^2\,d+10\,b^5\,c^3\right )-\left (5\,b^5\,c-5\,a\,b^4\,d\right )\,{\left (c+d\,x\right )}^4+a^5\,d^5-b^5\,c^5+{\left (c+d\,x\right )}^3\,\left (10\,a^2\,b^3\,d^2-20\,a\,b^4\,c\,d+10\,b^5\,c^2\right )+\left (c+d\,x\right )\,\left (5\,a^4\,b\,d^4-20\,a^3\,b^2\,c\,d^3+30\,a^2\,b^3\,c^2\,d^2-20\,a\,b^4\,c^3\,d+5\,b^5\,c^4\right )-10\,a^2\,b^3\,c^3\,d^2+10\,a^3\,b^2\,c^2\,d^3+5\,a\,b^4\,c^4\,d-5\,a^4\,b\,c\,d^4}+\frac {7\,d^5\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {c+d\,x}}{\sqrt {a\,d-b\,c}}\right )}{128\,b^{3/2}\,{\left (a\,d-b\,c\right )}^{9/2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c + d*x)^(1/2)/(a + b*x)^6,x)

[Out]

((79*d^5*(c + d*x)^(3/2))/(192*(a*d - b*c)) - (7*d^5*(c + d*x)^(1/2))/(128*b) + (49*b^2*d^5*(c + d*x)^(7/2))/(
192*(a*d - b*c)^3) + (7*b^3*d^5*(c + d*x)^(9/2))/(128*(a*d - b*c)^4) + (7*b*d^5*(c + d*x)^(5/2))/(15*(a*d - b*
c)^2))/(b^5*(c + d*x)^5 - (c + d*x)^2*(10*b^5*c^3 - 10*a^3*b^2*d^3 + 30*a^2*b^3*c*d^2 - 30*a*b^4*c^2*d) - (5*b
^5*c - 5*a*b^4*d)*(c + d*x)^4 + a^5*d^5 - b^5*c^5 + (c + d*x)^3*(10*b^5*c^2 + 10*a^2*b^3*d^2 - 20*a*b^4*c*d) +
(c + d*x)*(5*b^5*c^4 + 5*a^4*b*d^4 - 20*a^3*b^2*c*d^3 + 30*a^2*b^3*c^2*d^2 - 20*a*b^4*c^3*d) - 10*a^2*b^3*c^3
*d^2 + 10*a^3*b^2*c^2*d^3 + 5*a*b^4*c^4*d - 5*a^4*b*c*d^4) + (7*d^5*atan((b^(1/2)*(c + d*x)^(1/2))/(a*d - b*c)
^(1/2)))/(128*b^(3/2)*(a*d - b*c)^(9/2))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)**(1/2)/(b*x+a)**6,x)

[Out]

Timed out

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